Rotation rate of hour hand on clock?

AI Thread Summary
The rotation rate of the hour hand on a clock is calculated as 1/(12x60), equating to 1/720 revolutions per minute. This is derived from the fact that the hour hand completes one full rotation in 12 hours, which equals 720 minutes. The discussion clarifies that the relevant number is 12, as it represents the hours in a full rotation. Other options presented in the discussion are deemed incorrect. The consensus confirms that the correct answer is indeed 1/(12x60).
BioGuy
Messages
5
Reaction score
0
What is the rotation rate in revolutions per minute of the hour hand of a clock?

a.) 1/(12x60)
b.) 1/24
c.) 1/(24x60)
d.) none of these

I am not too sure how to answer this, i want to say its (a.) because it makes the most sense... ??any suggestions??
 
Physics news on Phys.org
How many minutes are there in 12hours (the time it takes to go around the clock?)
If you have N minutes/revolution - how do you get to revolutions/minute?

hint - if you are going 10miles/hour, what fraction of an hour does it take to go 1 mile
 
there are 720 minutes in 12 hours..

you invert(recipricol) of xmin/rev to get revolutions/min

im still a little lost... :-/ how can we disprove some choices?
 
one of the key differences in your choices are the numbers 12 and 24. What do they represent, and which one is relevant in the case of a full rotation of the hour hand?
 
BioGuy said:
there are 720 minutes in 12 hours..
you invert(recipricol) of xmin/rev to get revolutions/min
Exactly so the answer is 1/(12*60) = 1/720 as you said.
You don't need to disprove the others - they are just wrong!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top