Rotational Equilibrium Lab Question

AI Thread Summary
In a physics lab focused on demonstrating rotational equilibrium, the apparatus includes a boom and a tensioned string/pulley system. The forces are measured in Newtons, while the moment arms are in centimeters, raising a question about the necessity of unit conversion. It is confirmed that converting moment arm measurements to meters is essential for consistency in calculations, as the Newton is defined in terms of kilograms and meters. The discussion emphasizes the importance of ensuring all units align correctly for accurate results. Accurate unit conversion is crucial for successful lab outcomes.
CLeSure
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In my general physics lab, we are trying to show that certain systems are in equilibrium. The apparatus that we are using for rotational equilibrium consists of a boom resting on an axis point, attached to a string/pully that has a given tension.

The measured forces in the lab are in Newtons, but the measurements of the Moment Arms are in centimeters. Will I need to convert my measurements into meters before doing my calculations?

Thanks.

Chris
 
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CLeSure said:
In my general physics lab, we are trying to show that certain systems are in equilibrium. The apparatus that we are using for rotational equilibrium consists of a boom resting on an axis point, attached to a string/pully that has a given tension.

The measured forces in the lab are in Newtons, but the measurements of the Moment Arms are in centimeters. Will I need to convert my measurements into meters before doing my calculations?

Thanks.

Chris

What are the units of a Newton?
 
LowlyPion said:
What are the units of a Newton?

The forces were originally in grams, so we converted them to Newotons by mutliplying the mass by 10^-3, then multiplying b y 9.8 m/s So... the Newton would be Kg*m/s...

This is why I was thinking I had to convert my measurements to meters, so everything jived together. Am I correct in thinking this?
 
CLeSure said:
The forces were originally in grams, so we converted them to Newotons by mutliplying the mass by 10^-3, then multiplying b y 9.8 m/s So... the Newton would be Kg*m/s...

This is why I was thinking I had to convert my measurements to meters, so everything jived together. Am I correct in thinking this?

Most definitely.

Be more certain next time. Facts are facts.
 

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