Rottor of a vector in a simple way

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The discussion focuses on proving that the vector field F is conservative by showing that its curl (rot F) is zero. The vector field is expressed in both Cartesian and spherical coordinates, with the suggestion to use spherical coordinates for simplicity. A determinant method is provided for calculating the curl in both coordinate systems. The conversation emphasizes the importance of understanding the curl in curvilinear coordinates and references standard derivations found in multivariable calculus textbooks. Ultimately, the goal is to demonstrate that the radial vector field has a curl of zero, confirming its conservative nature.
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\vec{F}=(\frac{x}{\sqrt{x^2+y^2+z^2}},\frac{y}{\sqrt{x^2+y^2+z^2}},\frac{z}{\sqrt{x^2+y^2+z^2}})
<br /> \vec{r}=(x,y,z)<br />

<br /> |r|=\sqrt{x^2+y^2+z^2}

\vec{F}=(\frac{x}{|r|},\frac{y}{|r|},\frac{z}{|r|})

so its F=\frac{r}{|r|}

i need to prove that F is a conservative field
where (x,y,z) differs (0,0,0)
so i need to show that rot f is 0
but for rottor i need a determinant
is there a way to do a rot on simpler way?
 
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You have a radial vector. Look up "curl in spherical coordinates" and apply it.
 
The determinant method is usually the simplest way. In Cartesian coordinates, it's

\text{rot}\textbf{F}=\begin{vmatrix}\hat{x} &amp; \hat{y} &amp; \hat{z} \\ \partial_x &amp; \partial_y &amp; \partial_z \\ F_x &amp; F_y &amp; F_z \end{vmatrix}=\begin{vmatrix}\hat{x} &amp; \hat{y} &amp; \hat{z} \\ \partial_x &amp; \partial_y &amp; \partial_z \\ \frac{x}{\sqrt{x^2+y^2+z^2}} &amp; \frac{y}{\sqrt{x^2+y^2+z^2}} &amp; \frac{z}{\sqrt{x^2+y^2+z^2}} \end{vmatrix}

But since \textbf{F}=\frac{\textbf{r}}{r}=\textbf{e}_r, it is probably best to use spherical coordinates:

\text{rot}\textbf{F}=\begin{vmatrix}\textbf{e}_{r} &amp; r\textbf{e}_{\theta} &amp; r\sin\theta\textbf{e}_{\phi} \\ \partial_r &amp; \partial_{\theta} &amp; \partial_{\phi} \\ F_r &amp; r F_{\theta} &amp; r\sin\theta F_{\phi} \end{vmatrix}=\begin{vmatrix}\textbf{e}_{r} &amp; r\textbf{e}_{\theta} &amp; r\sin\theta\textbf{e}_{\phi} \\ \partial_r &amp; \partial_{\theta} &amp; \partial_{\phi} \\ 1 &amp; 0 &amp; 0 \end{vmatrix}
 
wow i how you came up with this kind of determinant
i am use the the first kind
 
In any 3D Curvilinear coordinate system (u,v,w), the rotation (or 'curl') is given by

\text{rot}\textbf{F}=\begin{vmatrix}h_u\textbf{e}_{u} &amp; h_v\textbf{e}_{v} &amp; h_w\textbf{e}_{w} \\ \partial_u &amp; \partial_v &amp; \partial_w \\ h_u F_u &amp; h_v F_{v} &amp; h_w F_w \end{vmatrix}

where \textbf{e}_u, \textbf{e}_v, and \textbf{e}_w are unit vectors that point in the direction of increasing u, v and w respectively, and h_u, h_v, and h_w are scale factors given by

h_u\equiv \left| \frac{\partial \textbf{r}}{\partial u} \right|

h_v\equiv \left| \frac{\partial \textbf{r}}{\partial v} \right|

and

h_w\equiv \left| \frac{\partial \textbf{r}}{\partial w} \right|

This is derived in most multivariable calculus textbooks.
 
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