- #1
jaysinghrath
- 1
- 0
If a point of the parabolic path the velocity be u and the inclination to the horizon be θ, at what time the particle is moving at right angle to its former direction.
I was trying to solve it using vectors.
My friend gave me a clue of applying some geometry to the parabolic path given below:-
He is definite that he solver it and the answer is = ucosec(θ)/g which is matching with the answer solving via vectors. Now he is not in contact, I was trying to solve this question.
PLZ help me
I was trying to solve it using vectors.
My friend gave me a clue of applying some geometry to the parabolic path given below:-
He is definite that he solver it and the answer is = ucosec(θ)/g which is matching with the answer solving via vectors. Now he is not in contact, I was trying to solve this question.
PLZ help me