Engineering Simple circuit, find equivalent resistance seen by the source

[qpham26]

Homework Statement

For the circuit shown in Figure, find the
equivalent resistance seen by the source. How much
power is delivered by the source?

http://sphotos-b.xx.fbcdn.net/hphotos-snc7/304377_496325960386924_988412599_n.jpg

Homework Equations

Req = R1R2 / R1+ R2

P = V^2 / R

Thanks you for your time.

The Attempt at a Solution

I am not understanding what they meant by "seem by the source"
so I assume that they want to find R equivalent for the whole thing.

Start from the right to left
2Ω + 1Ω = R_eq1 = 3Ω
R_eq1 || 3Ω = R_eq2 = 1.5Ω
4Ω + 1.5Ω+5Ω || 6Ω = R_eq3 = 3.82Ω
---->R_eqS = 3.82Ω + 7Ω = 10.82Ω
---->P_s = V_s²/ R_eqS = 18.11 W

 

[CWatters]

am not understanding what they meant by "seem by the source"
so I assume that they want to find R equivalent for the whole thing

.

Yes that is correct.

Imagine you were physically standing on the symbol for the 14V source voltage. What equivalent resistance do you "see" if looking to the right.

Your answers for the resistance and power are correct.