Engineering Simple Lazy Current Question (Circuit)

  • Thread starter Thread starter seto6
  • Start date Start date
  • Tags Tags
    Circuit Current
AI Thread Summary
In a circuit with a short path created by an inductor, the current will primarily take the shortest route, which is through the short circuit, rather than through the 12V and 4k ohm resistor. The resistance of a short circuit is effectively zero ohms, allowing maximum current flow through that path. The voltage divider equation is relevant when considering how voltage is distributed across components, but in this scenario, the presence of the short circuit negates the impact of the resistor. Current from the voltage sources will predominantly flow through the short circuit, minimizing the current through the resistor. Understanding these principles is crucial for analyzing circuit behavior in such configurations.
seto6
Messages
248
Reaction score
0
ok this is what i have, i want to know if the current would go through the 12V and 4k ohm resistor, since there is a short path (by making the inductor a short for time = infinity) would the current be lazy and take the path through the short or would it also go through the 12v and 4k ohm.

6f44ms.jpg
 
Physics news on Phys.org
seto6 said:
ok this is what i have, i want to know if the current would go through the 12V and 4k ohm resistor, since there is a short path (by making the inductor a short for time = infinity) would the current be lazy and take the path through the short or would it also go through the 12v and 4k ohm.

6f44ms.jpg

What are your thoughts? What is the resistance in Ohms for a short circuit? What is the voltage divider equation?
 
You must remember that the current through the short circuit comes from the two voltage sources.
 
Thread 'Have I solved this structural engineering equation correctly?'
Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...

Similar threads

Back
Top