Sin(Theta) or Cos(Theta) for Ramp problem

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The discussion revolves around determining the correct gravitational force component acting on a block on an incline in a pulley system. The user is unsure whether to use m1gsin(theta) or m1gcos(theta) to project the gravitational force parallel to the tension force T1. They are considering the scenario where theta equals zero to validate their choice. The focus is on accurately projecting gravity to solve for the moment of inertia of the pulley. Clarification on the correct gravitational component is essential for progressing with the problem.
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Homework Statement


http://i41.photobucket.com/albums/e271/FireFox988/l10g10.gif

The blocks shown in the figure below are connected by a string of negligible mass passing over a pulley of radius r = 0.250 meter and moment of inertia I. The block on the frictionless incline is moving up with a constant acceleration of magnitude a = 2.00 m/s2. What is the moment of inertia I of the pulley?

Homework Equations


Torque=I(alpha)
a=r(alpha)

The Attempt at a Solution


I solved using T1- m1gcos(theta) = m1a
Is it m1gsin(theta) or cos(theta) for the force of gravity on block one parallel to the T1 force. (like in eq. above or do i use m1gsin(theta))(don't help me solve the problem just want to make sure i projected the gravity on block1 correctly with the parallel force of tension)
 
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I always check my own choice by considering theta=0. Would you expect the component of gravity to be 0 or mg then?
 
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