Slipping rolling cylinder friction

AI Thread Summary
The discussion focuses on the friction involved when a cylinder rolls down an inclined plane without slipping, given a coefficient of friction μ. It clarifies that the friction force f must satisfy the condition 0≤f≤fmax, where fmax is defined as μN, the maximum frictional force available. If the required friction force exceeds fmax, the cylinder will slip instead of rolling. Participants confirm that as long as the friction force needed to prevent slipping is less than or equal to μN, the cylinder will roll smoothly. The key takeaway is that sufficient friction is necessary to maintain rolling without slipping.
xzibition8612
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Homework Statement



The cylinder is released from rest on the inclined plane. The coefficient of friction between cylinder and plane is μ. Determine the motion of the cylinder, assuming that μ is large enough to prevent slipping.

Homework Equations





The Attempt at a Solution


ok don't determine the motion. I have the solution in the textbook.

My question is about the friction. In my book it says "We are to assume the cylinder rolls. In this case the friction force f is an unknown and has a value satisfying 0≤f≤fmax where fmax=μN. After solving for f, we shall then impose the condition that it be less than μN, since we know the cylinder is not slipping"

Please note the friction vector is pointing to the right on the bottom of the cylinder.

I'm confused here about this friction. Why is f≤fmax? My intuition tells me if friction force is very big then the cylinder wouldn't roll. So if f≥fmax wouldn't the cylinder just not move? Why would it slip if f≥fmax? Thanks for explaining
 

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The amount of friction force you need to prevent slipping is f. As long as f turns out to be less than the max possible, which is μN, then things are good. But if the f needed is more than the surfaces can deliver, meaning if f > μN, then you'll begin to slip. Not enough friction is available.
 
so the maximum amount of friction available on this natural surface is uN. Meaning its not possible for f to be greater than this amount. So if it turns out f>uN, it means the cylinder will slip since not enough friction is present. Am I getting this correctly? Thanks.
 
xzibition8612 said:
so the maximum amount of friction available on this natural surface is uN. Meaning its not possible for f to be greater than this amount. So if it turns out f>uN, it means the cylinder will slip since not enough friction is present. Am I getting this correctly?
Yes. Exactly right.
 
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