Solution to Griffiths introduction to EM problem 2.26

AI Thread Summary
The discussion revolves around solving Griffiths' Introduction to Electrodynamics problem 2.26, which involves calculating the potential difference between two points on a conical surface with a uniform surface charge. Participants emphasize the importance of showing initial work to receive constructive feedback rather than asking for complete solutions. There is a suggestion to post the specific problem details for better assistance, as not everyone may have access to the textbook. The conversation highlights a common frustration with students seeking answers without engaging in the problem-solving process. Overall, the focus is on collaborative learning and the importance of effort in understanding complex topics.
question2004
Messages
8
Reaction score
0
Hi, there,

Could you please show me the solution to Griffiths Introduction to Electrodynamics, problem 2.26? The integral is so complicated. Thanks
 
Physics news on Phys.org
Cool! We're using the same textbook. Yeah, my next assignment will probably have problems from that section as well, since we're covering chapter 2 in the lectures right now. But, no one's going to do your homework for you. Show what you've got so far, and they'll help you out with corrections/point you in the right direction.
 
You might need to post the problem, since many you could help you may not have that text.
 
The problem is

A conical surface (an empty ice-cream cone) carries a uniform surface charge <sigma>. The height of the cone is h, and the radius of the top is R. Find the potential difference between points a(the vertex) and b (the center of the top)

Thanks a lot.
 
It could be worse!

I remember one post that said, in it's entirety, "What's the solution to the fourth problem on today's homework."

And another "What chapters will tomorrows test cover?"
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Contour integral and problem of Quantum mechanics (Griffiths)
Replies
1
Views
2K
Conical Surface Potential Difference
Replies
8
Views
4K
Electric potential of a conical surface
Replies
3
Views
3K
Electrical Potential of a uniformly charged spherical shell
Replies
5
Views
2K
Calculate electric force using Coulomb's law (vector components are the struggle)
Replies
3
Views
1K
I Controlling the location of a spark between two parallel rods
Replies
3
Views
1K
Voltage around a loop, half inside a capacitor and half outside
Replies
2
Views
1K
I Discontinuity of Electric field
Replies
7
Views
1K
[Special Relativity] - Finding Angle θ as Measured in Frame S
Replies
3
Views
1K
Solving Problem 4 of DJ Griffiths Electrodynamics Chapter 9
Replies
3
Views
4K

Hot Threads

Recent Insights

Back
Top