Solve KCL/MESH Problem: E=15V, R1=20k, R2=4.7k, R3=10k

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The discussion focuses on solving a circuit problem using Kirchhoff's Current Law (KCL) and Mesh analysis with given voltage and resistance values. The initial attempt at forming equations is criticized for incorrectly applying KCL and using voltage equations instead of current equations. The correct approach involves recognizing that the current through R1 is simply I1 and that KCL should be used to sum currents at nodes. Additionally, combining resistors in series and parallel is suggested as an alternative method to simplify the problem. Ultimately, using Norton’s equivalent or applying KVL in mesh analysis is recommended for finding the solution effectively.
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Homework Statement



circuit-1.jpg


Determine I_1 I_2 I_3
When
E = 15V
R1 = 20k ohms
R2 = 4.7k ohms
R3 = 10k ohms

Homework Equations



KCL equation

The Attempt at a Solution



i tried to find using KCL.. is my equation right?
Loop equation 1:
EB + I3R3 + R1(I3 + I1) = 0

Loop equation 2:
R1(I1 + I3) + R2(I1 – I2) = 0

Loop equation 3:
EB + I3R3 + I2R2 = 0

can i use MESH analysis... but there are three unknowns and if i use mesh, i can only have 2 equations with 3 unknowns
 
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Welcome to PF.

There is a problem with your equations.

The voltage across R1 is is simply R1*I1, not R1(I1 + I3), because the current flowing through R1 is simply I1.

Likewise, the voltage across R2 is R2*I2.

Also, these are KVL equations for voltage, not KCL which would apply to currents. KCL says that the sum of all currents entering a node is zero, and will be useful here.

Note, another way to solve this would be to use the rules for combining resistors in parallel and series.
 
I agree with Redbelly98, I think you're confusing KVL for KCL. See if you can combine the resistors to find the current coming out of the supply. From there, I think it's easier if you find the http://en.wikipedia.org/wiki/Norton_equivalent" equations. See link for quick wikipedia articles on them. Mesh analysis will work just fine here as well, but I think it's more obvious using Norton equivalent.
 
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u can apply kvl at the 2mishes and get 2equa., in 2variables .then solve them
 

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