The discussion focuses on solving Newton's Cooling Law to find the constant m given specific temperature readings over time. An object initially at 60°F cools to 45°F after 5 minutes and to 36°F after another 5 minutes. The relevant equation used is y = ce^(kt) + m, where the initial conditions lead to the equation c + m = 60. Participants suggest using the differential equation dT/dt = -k(T - T_ambient) to derive the necessary constants.
PREREQUISITESStudents studying physics or mathematics, particularly those focusing on thermodynamics and differential equations, as well as educators looking for practical examples of cooling laws in action.
Perhaps you should try solving directly from the formula for Newton's Law of Cooling.Nope said:Homework Statement
An object of temperature 60oF is placed in a medium maintained at a constant temperature moF. At the end of 5 mins thetemperature of the object is 45 oF and after another 5 mins its temperature is 36 oF.
Find m
Homework Equations
y=cekt+m
The Attempt at a Solution
when t=0,c+m=60
how would you find c and m??
thx