Solve Ramp with Friction: Coefficient of Kinetic Friction

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AI Thread Summary
The discussion revolves around calculating the coefficient of kinetic friction for a mass sliding down an inclined slide. The mass starts at a speed of 2.19 m/s and travels a distance of 2.5 m on a level surface after descending 1.07 m at an angle of 29.70°. Participants suggest using the conservation of energy principle, accounting for energy lost due to friction. The initial energy, which includes both potential and kinetic energy, must be equated to the final energy after accounting for friction. The problem is ultimately resolved by applying the appropriate energy equations.
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Homework Statement



When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 2.19 m/s. The mass stops a distance S2 = 2.5 m along the level part of the slide. The distance S1 = 1.07 m and the angle θ = 29.70°. Calculate the coefficient of kinetic friction for the mass on the surface

http://s876.photobucket.com/albums/ab327/rechitzy/?action=view&current=prob27a_MechEnWFriction.gif&newest=1

Homework Equations



E = K+U

The Attempt at a Solution



Don't even know where to start...
 
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You can use conservation of energy, taking into account the energy lost by friction.
 
ok i know what you are talking about but how do i do that?
 
Initial energy (potential+kinetic), minus the energy lost by friction, is equal to final energy (potential+kinetic). Write that out in an equation as your first step.
 
Ok, would this be KE1+PE1-Efr=KE2+PE2?
 
Thanks i already figured it out.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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