Solving Heat Loss from Hose with Radii R_i and R_o

[NotMrX]

Hello,

This problem has been messing me up.

A person waters their yard. He has a rubber hose cylinder with an inner radius,R_i[\tex], of 1.5 cm and an outer radius, R_o, of 1.7 cm. The thermal conductivity of of rubber is 0.2 in SI units. The hose is 5 meters long, L. The hose is completely in the air with a temp of 30 Celsius while the water has a temp of 20 Celsius. Ignoring the heat loss from the end what is the power or heat loss per second.<br /> <br /> Here is my attempt:<br /> P=K*A\frac{\DeltaT}{r}<br /> dA=L*2*\pi*dr<br /> P=K\frac{\DeltaT}{r}L*2*\pi*dr<br /> P=k*2*\pi*\DeltaT*L*Ln\frac{R_o}{R_i}<br /> <br /> It seems like something is wrong though.

 

[NotMrX]

Here is the question; I coulnd't get latex to work this time.

A person waters their yard. He has a rubber hose cylinder with an inner radius of 1.5 cm and an outer radius of 1.7 cm. The thermal conductivity of of rubber is 0.2 in SI units. The hose is 5 meters long, L. The hose is completely in the air with a temp of 30 Celsius while the water has a temp of 20 Celsius. Ignoring the heat loss from the end what is the power or heat loss per second?

 

[NotMrX]

Here is the question; I coulnd't get latex to work this time.

A person waters their yard. He has a rubber hose cylinder with an inner radius of 1.5 cm and an outer radius of 1.7 cm. The thermal conductivity of of rubber is 0.2 in SI units. The hose is 5 meters long, L. The hose is completely in the air with a temp of 30 Celsius while the water has a temp of 20 Celsius. Ignoring the heat loss from the end of the hose what is the power or heat loss per second?

Here is my attempt:
P=kA\frac{dT}{dr}[\tex]<br /> A=2L\pi(r_f-r_i)[\tex]&lt;br /&gt; dA=L\pidr&lt;br /&gt; P=k*dA

 

[Hootenanny]

While your having trouble with latex, what's your final answer?