Solving Unusual Problems: Using the Polytropic Ideal Gas Equation

AI Thread Summary
The discussion revolves around solving a complex problem using the polytropic ideal gas equation, specifically when cp is constant. Participants clarify the correct formula to use, which is (p2/p1)^(k-1)/k = T2/T1, with k set at 7/5. One user shares their calculations for temperature changes at different pressures, indicating a transition from 1 atm to 1.1 atm yielding 114 degrees and from 1 atm to 0.9 atm yielding 82 degrees. There is a focus on ensuring assumptions are clearly stated and the importance of showing all calculation steps. The conversation highlights the challenges of working with different units, such as Fahrenheit and psi, while confirming the validity of the math presented.
mulgerizze
Messages
3
Reaction score
0
Homework Statement
Exhaling air through a mask means the lungs needs to be pressurized to 1.1 atm instead of the normal 1atm. To exhale through the mask the lungs are depressurized to 0.9 atm. In either case the temp of the lungs wont be the normal 98.7 degrees Fahrenheit. What is the temperature swing of the lungs in this case?
Relevant Equations
Entropy, polytropic equation for an ideal gas
My teacher likes to make really weird problems. How can I start this problem? The only thing I thought of doing is using the polytropic ideal gas equation when cp= constant. (p2/p1)^k-1/k = T2/T1 and making p1 and t1 in each case the normal state of the lungs
 
Physics news on Phys.org
Hello (again),

And what do you get when you follow your thought ?

##\ ##
 
BvU said:
Hello (again),

And what do you get when you follow your thought ?

##\ ##
I got that the temperature from 1 atm to 1.1 atm was 114 and the temperature from 1 atm to 0.9 atm was 82
 
BvU said:
I suppose you used (p2/p1)^(k-1)/k = T2/T1 and not (p2/p1)^k-1/k = T2/T1
And k = 7/5 ?

I have trouble dealing with units like Fahrenheit and psi, but I suppose your math is ok.

So if your asumptions (did you list them ?) are correct, this is what omes out. Seems a bit hefty to me, but who knows ...

https://www.physicsforums.com/threads/homework-help-guidelines-for-students-and-helpers.686781/
(don't just dump a number, show your steps)

##\ ##
I assumed cp = constant and that the breathable air is an ideal gas.

My steps for for p=1.1 to p=1 k=1.4 were 98.7+460(1.1atm/1atm)^(1.4-1)/1.4

For p=0.9 to p=1 k=1.4 . 98.7+460(.9atm/1atm)^(1.4-1)/1.4
 
mulgerizze said:
Homework Statement:: To exhale inhale through the mask the lungs are depressurized to 0.9 atm.
Fixed typo for you in your problem statement. :smile:
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top