Someone check if this is correct: Finding force one object on another. Quick one

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To determine the force of package B on package A while both are sliding down a ramp with an acceleration of 1.8 m/s², the calculation uses the formula F = ma. Given that the mass of package B is 10 kg, the force exerted by package B on package A is calculated as F = (10 kg)(1.8 m/s²) = 18 N. The discussion also emphasizes the importance of considering frictional forces in the system, although specific values for friction were not provided. Participants are reminded to avoid creating multiple threads for the same problem to maintain clarity in discussions. The calculated force of 18 N is confirmed as correct under the given conditions.
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Homework Statement



The question asks me: Determine the force of package B on Package A.

Now package A and package B are sliding down a ramp together, so they have the exact same acceleration. The acceleration of the system is 1.8 m/s^2 and the mass of package B is 10kg

So, is it simply F = ma

F = (10kg)(1.8) = 18 N ?


Homework Equations





The Attempt at a Solution

 
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What is the problem you are working on, exactly as it was stated to you?
 
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C is the question I am trying to solve.
 
What did you use as the frictional force for the system?

How did you find it?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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