Special Relativity Math Thing (Fresnel's Drag Coefficient)

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Mark Zhu
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Homework Statement
Because v<<c in this case, we can expand the denominator
(1 + x)^-1 = 1 - x + ... keeping only the lowest term in x
v/c. The above equation becomes...
Relevant Equations
(1 + x)^-1 = 1 - x + ...
I am wondering if there is a typo in my textbook. Please see the attachment. The textbook says "...keeping only the lowest term in x = v/c." I am wondering if it should be "x = v/(nc)," as I circled in blue on the left side. It is a binomial expansion of the denominator. Shouldn't x be v/(nc) instead of v/c? The textbook says "...keeping only the lowest term in x = v/c." Thank you.
 
Attachments
  • Two-column textbook page on Fresnel's drag coefficient: left column solves u = (u' + v)/(1 + u'v/c^2) with u' = c/n, circled term 1 + v/(nc); right column expands (1 + x)^-1 = 1 - x + ... with x = v/c, leading to u = c/n + v - v/n^2.
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It doesn't make any difference. ##\frac v c## and ##\frac v {nc}## have the same order of magnitude.
 
What do you mean same order of magnitude? Isn't n the index of refraction?
 
Mark Zhu said:
What do you mean same order of magnitude? Isn't n the index of refraction?
It's ##\frac v c## that is important. You probably have ##n \approx 1## in any case.