Specific Heat Problem Help

[balllla]

Homework Statement

A .4lb piece of Hg at 210 F is placed in .3lb of water that has a temperature of 70.0f. The water is in .1lb brass calorimeter.

What is the final temperature of the mixture?

Homework Equations

Q=MC(deltaT)

The Attempt at a Solution

The part that I'm confused from is.

Qlost=Qgained
What is the final and initial temperature of the silver?
I can't figure that out from the problem, would the final temperature of the silver be 70.0degreeS?

 

[rock.freak667]

Qlost=Qgained
What is the final and initial temperature of the silver?
I can't figure that out from the problem, would the final temperature of the silver be 70.0degreeS?

The heat lost by the Hg = heat gained by the water + heat gained by the calorimeter

Initially, the water and calorimeter should be at the same temperature.

So can you formulate an expression for the given terms?

 

[balllla]

I cannot formulate an expression for the given terms. I've completed algebra, adv. algebra and now I am precalc and I just can't figure out the algebra to complete this practice problem.

 

[rock.freak667]

I cannot formulate an expression for the given terms. I've completed algebra, adv. algebra and now I am precalc and I just can't figure out the algebra to complete this practice problem.

Let's call the final temperature T_f


using Q=McΔT

What is the heat lost from the Hg?

 

[balllla]

Well I understand that -(Qloss)=Qgained and you need to get all variables to one side and other numbers on the other side, this is what i have done but I'm stuck

-(Qloss)=Qgained
-(Qloss silver)=Qgained of water=Qgainedofcalirmiter
-(mcdeltat)=mcdeltat+mcdeltat
-(181.8181g(.214cal/gc)(tf-98.8c)=(136.3636g(1cal)(tf-21.0c)+(45.454545g)(.0917cal/gc)(tf-21.0c)

okay this is what I have now I do not understand the algebra. ?

 

[rock.freak667]

Can you expand the brackets and then move all the T_f to one side?