Static equilibrium force decomposition problem

AI Thread Summary
The discussion focuses on a static equilibrium force decomposition problem involving torque calculations. Participants clarify that the torque equation includes terms for normal force and gravitational force, emphasizing the importance of using the perpendicular radius to correctly apply trigonometric functions. A misunderstanding regarding the signs of the trigonometric components is acknowledged, with one participant realizing their mistake in applying the angles. The correct torque equation is confirmed to be $$\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$$. Overall, the conversation highlights the significance of accurate angle representation in torque calculations.
Navyeel
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Homework Statement
I dont fully understand why the decompositions of forces.
Relevant Equations
F stands for friction, N is normalforce.
If you see the $\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$, all the trigonemetric parts are all opposite of what i can understand, given the angle as drawed in the Picture/url.

Please help me :)https://pasteboard.co/IiXr8qA.png
 
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I think I got it, my fault was that i forgot that in torque that if i use perpendicular radius i will get the cosines and the sinus parts correct :)
 
Yes it's always the perpendicular radius you need to use.

I note they are summing the torque about an axis at the top of the ladder.
 
Navyeel said:
If you see the $\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$
To get that LaTeX to render, you need doubled dollar signs like so:
$$\sum \tau_0 = L\cdot N_1 \cdot cos \theta - LF_1 sin \theta - L/2 \cdot G cos \theta$$
 
Ah ok, thanks :smile:
 
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