Statics: System in equilibrium - determine height (h)

AI Thread Summary
The discussion revolves around solving a statics problem involving a system in equilibrium, where the goal is to determine the height (h). The user initially struggled with the equations derived from the free body diagram but was able to set up two equations based on equilibrium conditions. After realizing a mistake in their calculations, they corrected their approach using the sine law, which led to new values for tension and angles. The corrected results yielded Td = 5.06 N, α = 27.99 degrees, and θ = 31.00 degrees. The conversation highlights the importance of accurate equation setup and calculation in solving equilibrium problems.
gate13
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Homework Statement



Good day to all,
I have been given a problem in statics, ore specifically a system that is in equilibrium, but a system I am having some trouble with. I have attached (in pdf) the problem's context and the free body diagram I have drawn.

The data we are give are as follows:
r = 0.575 m, a=1.05 m, W=4.905 N, Wc = 4.905 N

Homework Equations



We are asked to find h.

The Attempt at a Solution



What I have so far is as follows:

Using the fact the the hoop is in equilibrium, I obtained the two equations:

Td cos(θ) - Tccos(α) = 0 (along x-axis: \rightarrow)
Td sin(θ) + Tcsin(α) - W= 0 (along y-axis: \uparrow)

We know W and Tc and so we have two equations with three unknowns so far. Then I thought of using the problem's geometry to obtain a third equation.

Ans so using the sine law, I obtained:
\frac{sin180-α-θ}{a} = \frac{sin(α)}{r}

But when I try solving the system with the values, I get:
α=90, θ=88.17 and Td = -1* 10-81

which I am quite certain are wrong. I can't seem to pinoint the third equation to help solve the problem. Any help would be greatly appreciated.

Thank you.
 

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hi gate13! :wink:

gate13 said:
… But when I try solving the system with the values, I get:
α=90, θ=88.17 and Td = -1* 10-81

your method looks ok :confused:

show us how you got those figures :smile:
 
Hello tiny-tim,

First of all, I wish to thank you for taking time to answer my question. The values I listed above were obtained using a TI Voyage 200 calculator. What I entered (in the calclulator) was the following:
solve(Td*cos(theta)-Tc*cos(alpha)=0 and Td*sin(theta)+Tc*sin(alpha)-W = 0 and r*(180-alpha-theta) = a*sin(apha), {alpha, theta, Td})
I just realized I should be entering:
solve(Td*cos(theta)-Tc*cos(alpha)=0 and Td*sin(theta)+Tc*sin(alpha)-W = 0 and r*sin(180-alpha-theta) = a*sin(apha), {alpha, theta, Td}).
Upon correcting this, I obtained:
Td = 5.06 N, alpha = 27.99 degrees, theta = 31.00 degrees.

Once more I wish to thank you for your help ( and I feel a bit embarassed with respect to my mistake).
 
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