- #1
DevonZA
- 181
- 6
Homework Statement
Two lengths of steel plate 100mm wide and 15mm thick are riveted together by a single 18mm diameter rivet. If the joint carries a tensile load of 8kN calculate:
a) The shear stress in the rivet
b) The tensile stress in the perforated plate
Homework Equations
stress = force / cross sectional area
The Attempt at a Solution
a) stress = force / cross sectional area
= 8x10^3 / pi/4(0.018)^2
= 31.43MPa
This is the answer given in the textbook so I am satisfied it is correct.
b) This is where I am stuck.
The given answer is 6.51MPa.
I thought maybe if I use 100mmX15mm (1500mm) as the area for the plate and subtract the area of the 18mm diameter rivet (pi/4(0.018)^2) I could divide the 8kN force (although this is the tensile load of the joint) by this area and get the stress for the plate.
However if I do the above:
8x10^3 / [(1.5x10^-3)-pi/4(0.018)^2]
= 6.42MPa
Where am I going wrong?