The Internal Energy of Neon Gas

AI Thread Summary
The internal energy of neon gas is determined by its total kinetic energy, which can be calculated using the equation U = 3/2nRT. For the given conditions of 2 liters at 200 K and 0.7 atm, the density must be adjusted from standard conditions. The correct approach involves using the relationship U = (3/2)PV, where both pressure and volume are known. The calculations indicate that the internal energy can be derived directly from these parameters, simplifying the process significantly. Understanding that the internal energy of an ideal gas depends solely on pressure and volume is crucial for solving such problems.
PrideofPhilly
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Homework Statement



The internal energy of a monoatomic ideal gas such as neon is simply the total kinetic energy of all its atoms.

What is the internal energy of 2 liters of neon at a temperature of 200 K and pressure of 0.7 atm?

Homework Equations



PV = nRT
KE(ave) = 3/2kT
U = 3/2nRT

The Attempt at a Solution



KE = 1/2mv^2

From a previous problem, I figured out that v(rms) = 499.227 m/s.

And, 2 liters of neon X 0.9002 g/L (density of neon) = 0.0018004 kg

KE = 1/2(0.0018004 kg)(499.227 m/s) = 224.3546833 J (wrong answer)

I feel like I am approaching this problem in the wrong manner. Please help!
 
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That's the density of Ne at STP. What is the density at 200K and .7 atm?
 
So, d = P X MM/RT

d = (0.7 atm)(20 g/mol)/(8.31 J/mol*K)(200 K)
d= 0.008423586

2 L * 0.008423586 = 1.684717208E-5 kg

KE = 1/2(1.68E-5)(499.227 m/s)^2 = 2.09 J (WRONG ANSWER)

AM I USING THE WRONG UNITS OR DID I DO A MATH ERROR?
 
PrideofPhilly said:
So, d = P X MM/RT

d = (0.7 atm)(20 g/mol)/(8.31 J/mol*K)(200 K)
d= 0.008423586

2 L * 0.008423586 = 1.684717208E-5 kg

KE = 1/2(1.68E-5)(499.227 m/s)^2 = 2.09 J (WRONG ANSWER)

AM I USING THE WRONG UNITS OR DID I DO A MATH ERROR?

I'd say your numbers are wrong, because without even looking you had .0018 kg using STP. I wouldn't expect such a small number after accounting for the 200/273 ratio and the .7 ratio.

Won't the approach work out to be more like (P1/T1)/(P2/T2) = d1/d2 ?
 
I may be missing something but it looks from the revelant equations that
U=1.5*(R/M)*T where R is the universal gas constant, M is the molecular weight of neon and T is temperature in deg K. Am I over simplifing this?
 
The solution to the problem is startlingly simple; you were less than a hair away from getting it. You wrote, as a relevant equation, U = 3/2nRT. You also wrote PV = nRT. So if U=(3/2)PV, and you have both P and V.

Remember this neat result: the internal energy of an ideal gas depends only on its pressure and volume.
 
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