TheoMech - rolling a ball down a curve

AI Thread Summary
The discussion revolves around analyzing the forces acting on an object rolling down a curve defined by a function y=f(x) under the influence of gravity, without friction. Participants explore the independent forces in both x and y directions, seeking to understand the application of Lagrangian mechanics to determine acceleration. The conversation highlights the normal force being orthogonal to the curve's slope, leading to questions about the presence of forces in the x direction. It is noted that if the x-axis is oriented perpendicular to gravity, there would be no force acting in the x direction. The discussion ultimately emphasizes the importance of correctly defining axes to analyze the forces effectively.
K.J.Healey
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This isn't a homework question (im not in school) but its nearly one for a Theomech class, or maybe just dynamics. Maybe I'm just not seeing it.


Assume you have a hill that's defined by some part of a function y=f(x) (like exponentially decreasing, or a sine wave)

and you put an object on top and let it move down the curve.
assume no friction, there is some gravity force in the y direction only.

What are the independent forces of the object at a given x direction?

so I am looking for Fx(x,f(x)) and Fy(x,f(x)) so get the force given some euation describing the curve and a position.

Would I use lagrangian mechanics to pull out the accel in each direction? or what...

thanks
 
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heres what I've come up with so far

assuming the equation f(x), the vector describing the direction of increase from the current point xo, would be :

Vi = {f(xo+dx) - f(xo), xo} (haha, I've seen that somewhere before...)

ok, so the normal force would be orthogonal to this vector.

Vn = -dx*i + (f(xo+dx)-f(xo))*j

so Fn = |Fn|*Vn
and Fn_x = -dx

wait wait wait, so this DOESNT feel a force in the X direction? I mean if take the limit and dx->0... am I doing this the wrong way?

Its basically looking at the gradient of something... why don't i remember this stuff...
 
If you are referencing your x-axis perpendicular to g, then no there is no force in the x direction. Personally, I would set the axis such that x is along the average of the function of the path of decent, y being perpendicular, g will be a resultant of two vectors, Gx and Gy. I'm not really sure what your trying to do though, so...
 
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