Thermal Conductivity - Estimate Temperature

unscientific
Messages
1,728
Reaction score
13

Homework Statement



2mxl49.png


Given an insulating case outer surface at 25C, radiates heat to surroundings at 20C. Find temperature inner surface.

Homework Equations





The Attempt at a Solution



The heat is conducted through a thickness of 2.5mm, with a temperature difference of 5oC. Thus ##\frac{\partial T}{\partial z} = 2000##. Using ##k = 0.02##:

We have a value for the flux:

J = k\frac{\partial T}{\partial z} = 40

Using Stefan's Law:

J = \sigma T^4

We get ##T = 163K##, and boy that is one cold case!(-110oC)
 
Physics news on Phys.org
You seem to think the 5oC difference is between the iPod and the outside of the case.
Looks to me as if that temperature difference is to be calculated from the flux.
Stefan's law works two ways: 25 to 20 should be something like J = \sigma \left ( T_{\rm case}^4 - T_{\rm environment}^4 \right )
 
BvU said:
You seem to think the 5oC difference is between the iPod and the outside of the case.
Looks to me as if that temperature difference is to be calculated from the flux.
Stefan's law works two ways: 25 to 20 should be something like J = \sigma \left ( T_{\rm case}^4 - T_{\rm environment}^4 \right )

That's right, because ##J## is the net flux (caused by a temperature gradient). The answer turns out to be ##26.8^o##, which looks right.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top