Thermal Expansion of a copper cylinder

amiv4
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Homework Statement



A copper cylinder is initially at 20.0 C

Homework Equations



At what temperature will its volume be 0.150 % larger than it is at 20.0 C

The Attempt at a Solution



\DeltaV =betaV\DeltaT

.15=5.1x10^-5(Tf-20)
 
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Hi amiv4,
Welcome to PF.
Δv = 0.150% = 0.15/100 m^3
 
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