Thermal radiation and copper

[nithin]

I have a question. Assuming I have oil at 80 degrees in a copper calorimetry cup , will the heat loss by thermal radiation be very high and will it affect my values?

I am thinking that it would not and that it would be negligible. But i do not know why. I heard somewhere that it would be high due to copper not having a dipole movement. Can someone please explain to me why?

 

[Mentz114]

Your own experience with hot drinks surely tells you that a liquid at 80C cools pretty quickly whatever its in.

Copper is a very good conductor of heat and has a low heat capacity so it won't help much to keep the oil warm.

The heat capacity of a substance depends on its internal degrees of freedom for vibration, that's where the atomic dipole movement comes in.

 

[Astronuc]

I have a question. Assuming I have oil at 80 degrees in a copper calorimetry cup, will the heat loss by thermal radiation be very high and will it affect my values?

I am thinking that it would not and that it would be negligible. But i do not know why. I heard somewhere that it would be high due to copper not having a dipole movement. Can someone please explain to me why?

See the discussion of radiation heat transport and the Stefan-Boltzmann Law
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/stefan.html

Let T_hot = 80°C or 353 K and T_cold = 25° or 298 K. One must use absolute temperature in the S-B law.