Thermodynamics of a floating cylinder

AI Thread Summary
The discussion focuses on calculating the energy associated with the buoyancy of a deformed water surface caused by a floating cylinder in an infinite tank. The user seeks to compare the energy of a flat liquid surface to that of a deformed surface, specifically analyzing the buoyancy effect without considering the liquid displaced by the cylinder itself. The reasoning involves integrating the buoyancy force over the depth of the liquid, using pressure and area to derive the energy difference. Key parameters include liquid density, gravitational acceleration, and the geometry of the meniscus formed by the cylinder's displacement. The inquiry raises questions about the buoyancy of a depressed liquid surface and its implications in the context of thermodynamics.
private_donkey
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I am wondering if my reasoning is correct for determining the energy due to the buoyancy of a deformed water surface.

Essentially, one has a floating cylinder that depresses the surface of a liquid in an infinite tank as seen in the figure. I want to compare the energy of a flat surface with the energy of the deformed surface due to the displacement of the liquid by air (I know there are other energies involved but for the time being I am only looking at the energy due to the buoyancy of the displace liquid due to the deformed surface), not including the liquid displaced by the cylinder.

My reasoning is
<br /> \begin{align}<br /> E_{deformed} - E_0 &amp;= \int_0^{-h} -F_{buoyancy} dz \\<br /> &amp;= \int_0^{-h} -P A dz \\<br /> &amp;= \rho g \int_0^{h} z \pi f(z)^2 dz<br /> \end{align}<br />

where \rho is the density of the liquid. P is pressue, given by P = \rho g z, A is area, and thus A dz is volume of the displace liquid. A can be given by A = \pi f(z)^2, where f(z) describes the radius from the centre of the cylinder to the edge of the meniscus to make infinitesimal disks as a function of z. g is gravity accel.

Is this reasoning correct?
 

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