Engineering Thevenin equivalent of an LED circuit

AI Thread Summary
Determining the Thevenin equivalent of a circuit with a battery and an LED is challenging due to the non-linear nature of LEDs, which do not exhibit a linear voltage-current relationship. While Thevenin's theorem typically applies to linear components, the LED can be approximated as a resistor in its ON state for small current variations. The variational impedance can be calculated using the relationship between current and voltage, leading to a formula involving electronic charge and temperature. However, modeling the LED as a standard diode for this purpose may not be entirely valid. Overall, the discussion highlights the complexities of applying Thevenin's theorem to circuits with non-linear components like LEDs.
Marshillboy
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Homework Statement


How would I go about determining the Thevenin equivalent of a simple circuit involving a battery and an LED? I suppose there could be a series resistor to prevent excess draw and burning out of the diode.

This question seems very odd since LEDs by definition don't involve a linear relationship between voltage and current.


Homework Equations


Thevenin's theorem


The Attempt at a Solution


Not sure how to go about starting this.
 
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Marshillboy said:

Homework Statement


How would I go about determining the Thevenin equivalent of a simple circuit involving a battery and an LED? I suppose there could be a series resistor to prevent excess draw and burning out of the diode.

This question seems very odd since LEDs by definition don't involve a linear relationship between voltage and current.


Homework Equations


Thevenin's theorem


The Attempt at a Solution


Not sure how to go about starting this.

The LED is a nonlinear component, as you say. There is no such thing as a Thevenin equivalent for a component or network including a nonlinear component.

However, if you consider the LED in its ON state, then you can model it as a resistor for small current variations. If the LED is modeled as a standard diode (which I'm not sure is an entirely valid thing to do), then

i = i0eqV/kT
so the variational impedance is Rvar= 1/(∂i/∂V) and so
(∂i/∂V) = qi/kT or Rvar = kT/qi
where
q = electronic charge
k = Boltzmann's constant
T = Kelvin temoperature.
At room temperature, kT/q ~ 26mV.
 

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