Thevenin Equivalent Resistance for a Black Box

AI Thread Summary
The discussion revolves around finding the theoretical Thevenin equivalent resistance for a black box, where the measured value is approximately 4786Ω, while the calculated theoretical value is around 3511Ω. The user has attempted various calculations, including parallel and series combinations of resistors, but is struggling to reconcile the two values. Suggestions include using nodal analysis for a simpler solution and ensuring that the DC voltage source is shorted during measurements. Additionally, verifying the actual resistance values of the components and connections in the circuit is recommended to ensure accuracy.
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Homework Statement


I am trying to find the theoretical Thevenin equivalent resistance for a black box that I used in an experiment. The measured Thevenin equivalent resistance was roughly 4786\Omega. However, I have tried several times to solve the problem, but keep arriving at a theoretical value of around 3511\Omega. That just seems to be a little too low...

I have attached the circuit schematic, with resistor values included.
Could someone please look at the problem and see if I am on the right track. If so, any pointers on how I should finish it?

Homework Equations


R_{Th}= V_{Th}/I_{sc}
Resistors in Parallel: R_{eq}= (1/R_{1}+...+1/R_{n})^{-1}
Resistors in Series: R_{eq}=R_{1}+...+R_{n}
Y to Delta Transformation:

The Attempt at a Solution


STEP ONE: R2, R3 in parallel
R23 = [(1/R2)+(1/R3)]^-1 = [(1/9.97k\Omega)+(1/1.001k\Omega)]^-1 = .9096k\Omega

STEP TWO: R23 IN SERIES WITH R5
R235 = R23 + R5 = .9096k\Omega + 10.0k\Omega = 10.9096k\Omega

STEP THREE: Y TO \Delta TRANSFORM R4, R6, R7
Rc = [(R4*R6)+(R4*R7)+(R6*R7)]/R4 = 24.95k\Omega
Ra = [(R4*R6)+(R4*R7)+(R6*R7)]/R6 = 24.85k\Omega
Rb = [(R4*R6)+(R4*R7)+(R6*R7)]/R7 = 12.39k\Omega

STEP FOUR: Rc PARALLEL to R235
[(1/24.95k\Omega )+(1/10.9096\Omega )]^-1 = 7.59k\Omega

From here, I have tried different combinations of source transformations, converting the delta back to a Y, etc. to try and get an equivalent resistance.
 

Attachments

  • theveninpf.jpg
    theveninpf.jpg
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If you post your image on a free image hosting site, and put the link here, we won't have to wait for the attachment you already posted to be approved.
 
The Electrician said:
If you post your image on a free image hosting site, and put the link here, we won't have to wait for the attachment you already posted to be approved.

Thanks for the tip. I've uploaded it:

http://www.mountainescapesproperties.com/theveninpf.jpg"
 
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Have you studied any of the general network solution techniques, such as the nodal method or the loop method?

If you were to use the nodal method, you only have 3 nodes in this circuit, and the solution would be fairly straightforward.

You are assuming the DC voltage source has zero internal resistance, right?
 
By the way, notice that R2, R3 and R4 are all three in parallel. If you replace then by their equivalent, and replace R5 and R6 by an equivalent, you will have a simple ladder network. You can then work that out very easily, without any need for delta-y or similar transformations.
 
I get 3784.959 for the theoretical value.

I assume you got your measured value in the lab with a simple ohmmeter measurement. Did you remember to replace the DC voltage with a short circuit before you made your measurement?
 
The Electrician said:
I get 3784.959 for the theoretical value.

I assume you got your measured value in the lab with a simple ohmmeter measurement. Did you remember to replace the DC voltage with a short circuit before you made your measurement?


Thanks for all of your advice.

I came to my measured value of R_th by measuring the open circuit DC voltage between the terminals of the black box (V_th) and then measuring short circuit DC current between the terminals of the black box (I_sc)
then calculating R_th = (V_th)/(I_sc)...
 
Well, that should work.

I think if I were you, I would get an ohmmeter and verify that the resistance of each of the resistors in your circuit is what you think it is. Also verify the connections.
 
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