Top speed of vehicle on a curved road

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The discussion revolves around calculating the top speed of a vehicle navigating a curved road with a radius of 31.5 meters, given a coefficient of static friction of 0.800. The key equations involved are the centripetal acceleration formula (Ac = V^2/r) and the force equations for friction and centrifugal force. Participants emphasize the importance of drawing a force diagram to visualize the forces acting on the vehicle, including weight, centrifugal force, and friction. The frictional force is determined by multiplying the coefficient of friction by the normal force, which is equal to the weight of the car. Ultimately, the solution involves equating the outward centrifugal force to the inward frictional force to solve for the maximum speed, V.
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Homework Statement



Fifteen clowns are late to a party. They jump into their sporty coupe and start driving. Eventually they come to a level curve, with a radius of 31.5 meters. What is the top speed at which they can drive successfully around the curve? The coefficient of static friction between the car's tires and the road is 0.800.

Homework Equations



Ac=V^2/r
Fc=mv^2/r


The Attempt at a Solution



I don't know...i'm kinda confused on this problem
 
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In mechanics the first step is always to draw a diagram of the forces.
You have the weight of the car (acting downwards) the centrifugal force acting outward parralel to the rowd and friction acting inward (opposing the outward slide)

Note, Friction force is = friction coef * downward force.
 
hmm i know F,friction= coef friction x normal force...but its still not helping me
 
You know the outward force F = m V^2 / r
You know the frictional force resisting this F = cf * weight = cf m g

Set these equal and solve for V, note that m cancels, you don't need to know it.
 
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