How can I do this?Calculating Torque on a Dam Gate Hinged at the Water Surface

AI Thread Summary
To calculate the torque on a dam gate hinged at the water surface, one must consider the varying water pressure with depth. The force on a thin horizontal strip of the gate can be determined using the equation f(h) = p(h) × w × dh, where p(h) is the pressure at depth h and w is the width of the strip. The torque is then calculated by integrating the expression (h - h_pivot) × f(h) from the top to the bottom of the gate. The integration limits should reflect the height of the pivot and the dimensions of the gate. Proper integration will yield the total torque acting on the gate.
gunnar
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There is a gate in a dam. The upper edge of the gate runs along the water surface. The gate is 2 m high and 4 m wide and is hinged along a horizontal line through its center. I have to calculate the torque about the hinge arising from the force due to the water. I know how to calculate torque and water pressure with depth but I have no clue about this problem, I got a clue that tells me to calculate the torque of a thin horizontal strip at a depth h and integrate this over the gate, how should I do that. If someone has a clue, please help me.
 
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gunnar said:
There is a gate in a dam. The upper edge of the gate runs along the water surface. The gate is 2 m high and 4 m wide and is hinged along a horizontal line through its center. I have to calculate the torque about the hinge arising from the force due to the water. I know how to calculate torque and water pressure with depth but I have no clue about this problem, I got a clue that tells me to calculate the torque of a thin horizontal strip at a depth h and integrate this over the gate, how should I do that. If someone has a clue, please help me.

Calculate the hydrodynamical force with which the water acts upon the dam's gate.Use particular geometry of the problem (meaning the perpendicularity between the force and the distance between the point of application and the the center of rotation) to find the torque.

Daniel.
 
There is in fact no problem finding the force on, let's say the bottom of the gate, but the force is not constant on the whole gate because deeper you go into the water, more pressure there is, isn't that correct. So I think my biggest problem is finding a equation for the variables and integrating it, and that's where I'm stuck
 
gunnar said:
There is in fact no problem finding the force on, let's say the bottom of the gate, but the force is not constant on the whole gate because deeper you go into the water, more pressure there is, isn't that correct. So I think my biggest problem is finding a equation for the variables and integrating it, and that's where I'm stuck

It seems like a pretty straightforward problem. Let's take a look at a thin layer of water at height h. Then we can say that the water pressure at that height is p(h). (We can assume that water pressure at a particular depth is constant.)

Now, the force exerted by water is equal to the pressure multiplied by the area. The area of a thin strip of the gate is going to be w \times dh. So the force at a particular depth will be f(h)=p(h)\times w \times dh. The torque due to the force is going to be (h-h_{pivot}) \times f(h), so all you have to do is integrate that from the top of the gate to the bottom:
\int_{h_{min}}^{h_{max}} (h-h_{pivot}) p(h) w dh

Remeber that the sign depends on how your coordinates are set up.
 
OK. Let's see If I got this right.
Lets say that the pivot has height 0 meters, the top of the gate then is 1 and the bottom is -1

The equation that I came up with looks like this:

Torque(h)= (Po + density*g* -h)-4h

What I don't know is how to integrate this equation

I guess I have to integrate once with the limits 0 to 1 and then once with 0 to -1
that way I get the torque on either side of the pivot
 
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