Torque - Finding the unknown weight

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The discussion focuses on using torque to find the weight of an unknown object attached to a pole. A 10.0 m pole weighing 20.0 N has its center of gravity 2.00 m from one end, with the unknown weight hanging at the opposite end. The balancing point is 2.00 m from the unknown weight, leading to the equation Tcw = Tccw. By solving the torque equation, the unknown weight is determined to be 60.0 N. The user expresses gratitude for the assistance received in solving the problem.
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Homework Statement


Torque is used to determine the weight of an object. A 10.0 m long pole weighing 20.0 N has its center of gravity 2.00 m from one end. An object of unknown weight is hung at the end opposite the center of gravity. With the object hanging at this end, the pole now balances 2.00 m from the unknown weight. What is the weight of the unknown weight? Ans:60.0


Homework Equations


T = F * R


The Attempt at a Solution


T = 20 * 2
= 40 ?

:(
 
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oh please anyone? my exams tommorow? I am sorry for being so naggy? any help AT ALL will be great. anything. I've been staring at this screen refreshing every 5 seconds.
 
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Ok let me have a crack at it.I assume that unknown object is at the other end of stick (not the center of gravity end). So

Tcw = Tccw
2*X = 6*20
X=60 N
 
Thank you so much. So, SO much. I love you. In a non-gay way. <3
 

Thread 'Errors and significant figures'

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Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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