Comparing Moments: Do These Two Pictures Have the Same Torque?

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AI Thread Summary
Both pictures in the discussion exhibit the same torque due to their identical perpendicular components of force relative to the length L. The torque is calculated using the formula t = rF, confirming that both scenarios yield the same moments. The right-hand rule is applied consistently, indicating that the direction of torque is also the same. This analysis supports the conclusion that both images indeed have the same moments. The discussion effectively clarifies the relationship between force components and torque.
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Homework Statement



Do both these two pictures have the same moments?

j5z43t.jpg



315236g.gif


Homework Equations



t=rF

The Attempt at a Solution



Yes, if you use the formula, you will notice they have the same moments and direction (using right hand) . Is this correct?
 
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NoobeAtPhysics said:
Yes, if you use the formula, you will notice they have the same moments and direction (using right hand) . Is this correct?
Yep. Only the component of force perpendicular to the length L contributes to the torque about point A. The perpendicular component is the same in both cases.
 
thank you doc AI san
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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