Torque: Find Length of Moment Arm & Calculate Magnitude/Sign

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The discussion focuses on calculating the moment arm length and torque magnitude/sign related to a force vector about a point. The moment arm is defined as the perpendicular distance from the line of action of the force to the point of interest. The torque is calculated using the formula torque = magnitude of force times the moment arm, with the sign determined by the direction of rotation: counterclockwise is positive and clockwise is negative. Clarification is provided that the moment arm is not represented by dashed lines extending from the force vector but is specifically the perpendicular distance to the point. Understanding these concepts is crucial for accurately determining torque in physics problems.
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Homework Statement


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a) What is the length, rmr_m, of the moment arm of the force F→F_vec about point p?

b) Find the torque τtau about p due to F→F_vec. Your answer should correctly express both the magnitude and sign of τ.

The Attempt at a Solution

a) I'm inclined to state the answer as -rsinΘ but apparently the answer is r sin Θ.
Is there a reason why the sign is positive?
 
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negation said:

Homework Statement


View attachment 68238

a) What is the length, rmr_m, of the moment arm of the force F→F_vec about point p?

b) Find the torque τtau about p due to F→F_vec. Your answer should correctly express both the magnitude and sign of τ.


The Attempt at a Solution




a) I'm inclined to state the answer as -rsinΘ but apparently the answer is r sin Θ.
Is there a reason why the sign is positive?
always use the magnitude ( positive number) of the force and position vectors and moment arm when calculating torques. The sign of the torque is then determined by clockwise or counterclockwise torque , ccw is plus in this example, cw is minus, simply by convention.
 
PhanthomJay said:
always use the magnitude ( positive number) of the force and position vectors and moment arm when calculating torques. The sign of the torque is then determined by clockwise or counterclockwise torque , ccw is plus in this example, cw is minus, simply by convention.

Understood.

What about (b)? I'm really quite unclear about what moment of arm is and how it relates to torque. Would you mind shedding some light? (I appreciate)
 
negation said:
Understood.

What about (b)? I'm really quite unclear about what moment of arm is and how it relates to torque. Would you mind shedding some light? (I appreciate)
There are several ways to calculate torque about a point. One such way is to use torque = magnitude of force times the perpendicular distance from the line of action of the force to point, where the perpendicular distance is called the 'moment arm'. Another is to use the cross product rule. Sign of torque is plus if ccw, minus if cw, using the convention that ccw torques are positive.
 
PhanthomJay said:
There are several ways to calculate torque about a point. One such way is to use torque = magnitude of force times the perpendicular distance from the line of action of the force to point, where the perpendicular distance is called the 'moment arm'. Another is to use the cross product rule. Sign of torque is plus if ccw, minus if cw, using the convention that ccw torques are positive.


And the dashed lines extending from F vector is the moment arm?
 
negation said:
And the dashed lines extending from F vector is the moment arm?
No, the moment arm is the perpendicular distance from the line of action of the force vector to the point, which woukld be rm on your sketch.
 
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