Total moment of shear stress about the center line of a cylinder

AI Thread Summary
The discussion focuses on calculating the total moment of shear stress about the center line of a cylinder, specifically addressing the integration process involved. The shear stress of the inner cylinder is confirmed to be 405 Pa. The term d(theta) in the moment expression arises from the need to integrate the shear stress around the cylinder's circumference. A differential force, represented as dF, is defined as the product of shear stress, the length of the cylinder, the inner radius, and d(theta). Understanding this integration is crucial for accurately visualizing the total moment of shear stress.
eterna
Messages
19
Reaction score
0
http://postimg.org/image/onxjqc26l/

I have found the shear stress of the inner cylinder to be 405 Pa like in the solution
but I am having trouble visualizing the total moment of this stress about the center line.
I was wondering if someone could explain where that d(theta) in the moment expression comes from, possibly with a diagramthanks
 
Last edited by a moderator:
Physics news on Phys.org
The d(theta) comes in because you have to integrate around the circumference of the cylinder. The force on a differential area of the cylinder is ##dF=\tau (L r_id\theta)##.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top