Total resistance through cubic circuit

AI Thread Summary
The discussion focuses on calculating the equivalent resistance between two diagonally opposite corners of a cube made up of 12 resistors. Participants express uncertainty about the algebraic approach to the problem, debating whether to apply Kirchhoff's laws directly or to visualize the cube in a flattened format. There is confusion regarding the connections between nodes and how to account for them in the calculations. Suggestions include simplifying the circuit by considering the symmetry of the cube and the paths between nodes. The conversation highlights the complexity of analyzing the circuit while seeking clarity on the best method for solving the problem.
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Homework Statement



Suppose a resistor R lies along each edge of a cube (12 resistors in all) with connections at the corners. Find the equivalent resistance between two diagonally opposite corners of the cube


Homework Equations



\SigmaI = 0 at a node (a junction)

\SigmaV = 0 through a loop

V=IR

The Attempt at a Solution




Not quite sure how to do this one algebraically. Would I just add up all the V/Is? how?
 
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Not quite sure where to start...can anyone help me?
 
How about opening the cube out so it's flat and looking at it that way.
 
Interesting...is that necessary though, or could I just apply kirchhoffs laws to it as it is?
 
I count from anyone node:
3 paths to 3 nodes which then connect by:
6 paths to 3 nodes which then connect by:
3 paths to 1 node.

connecting the 3 nodes together with wires should change nothing.
 
are you saying just ignore those 6 connections?
 
I think the post I was responding to was deleted.
 

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