How to Calculate Transmission Line Coefficients?

AI Thread Summary
The discussion focuses on calculating transmission line coefficients using the ABCD parameters for a high-voltage transmission line operating at 50 Hz. The user is working on determining the primary line coefficients R, L, G, and C based on given values and an open-circuit voltage of 88.9 kV. The calculations involve complex impedance and admittance, leading to the derivation of coefficients per kilometer for resistance, inductance, and capacitance. The user seeks validation of their approach and calculations, particularly regarding the relationship between the components in the circuit model. Overall, the thread emphasizes the application of transmission line theory in practical calculations.
Jason-Li
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Homework Statement


Figure shows a 50 Hz, high-voltage, transmission line. The relationships between the sending and receiving end voltages and currents are given by the complex ABCD equations:

mimetex-cgi-20v_s-v_r-a_1-ja_2-i_r-b_1-jb_2-gif.gif


mimetex-cgi-20i_s-v_r-c_1-jc_2-i_r-d_1-jd_2-gif.gif


where 'S' stands for sending-end and 'R' stands for receiving-end

(a) Given the parameter values in TABLE C and an open-circuit received voltage measured as 88.9 kV, calculate the values of
mimetex-cgi-20v_s-gif.gif
and
mimetex-cgi-20i_s-gif.gif
and hence the power
mimetex-cgi-20p_-so-gif.gif
absorbed from the supply by the transmission line on open circuit.

(b) If the line is modeled by the T-circuit of FIGURE 3(b), see if you can estimate the primary line coefficients R, L, G and C. The line is 50 km long.

upload_2019-3-4_11-6-3.png

The Attempt at a Solution


I am currently doing part (b), if

[ A B ] = [ 1+Z1*Y2 Z1+Z3+Z1*Y2*Z3 ]
[ C D ] = [ Y2 1+Y2*Z3 ]

Then Y2 = C =j0.001349S
Also A=1+Z1*Y2
Z1= (A-1)/Y2
Z1=(0.8698+j0.03542-1) / j0.001349
Z1= 26.268+j96.558 Ω
Z1=Z3
So as Z1 & Z3 in series:
R+jXL = Z1*2
R+jXL = 52.536+j193.116 Ω
R coefficient = R / 50 = 1.051Ω/km
L= XL / 2πf = 193.116 / 2π*50 = 0.614707H
L coefficient = 0.614707 / 50 = 12.294mH/km
G coefficient = 0 as Y2 branch is not resistive only 'imaginary'
XC = 1 / Y2 = -j741.290 which is capacitive
C= 1/ XC*2πf = 1 / j741.290*2π*50 = 4.29μF
C coefficient = 4.29μF / 50 = 85.88pF/km

How does that look to you smarter people?
 

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In my opinion Z3 is parallel with 1/Y2 and the total Z [if VR=0] has to be Z1+Z3||1/Y2
 
Last edited:
Sorry, it could be better using D=IS/IR =Z3||1/Y2 divided by Z3
 
Hi Babadag,

I would've likely said the same however in my learning materials the below is stipulated. I then equated that each as appropriate. Any ideas?

upload_2019-3-6_20-32-20.png
 

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It is o.k. and for the record Z1=Z3 indeed.
 

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