Transverse wave through a wire, and tension.

AI Thread Summary
The discussion focuses on calculating the tension in a wire based on a transverse wave equation. The wave has a linear density of 2.35 g/m and is described by the equation y(x,t) = (1.4 cm)sin[(5.45 m⁻¹)x−(6950 s⁻¹)t]. Initial calculations for maximum velocity and wave speed were attempted, leading to an incorrect tension value. Clarification was provided that 6950 is indeed the angular frequency (omega), which helped resolve the confusion. Ultimately, the correct tension was calculated as approximately 22.25 N.
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A transverse wave in a wire with a linear density 2.35 g/m has the form y(x,t) = (1.4 cm)sin[(5.45 m-1)x−(6950 s-1)t].
What is the tension?


I took the A=.014m, k=5.45 /m, and \omega=6950.

I used the formula for the max velocity = A\omega
v=(.014)(6950)=97.3

Then I used the formula for the speed of a wave on a string v=\sqrt{\frac{F}{M/L}}.
97.3=\sqrt{\frac{F}{.00235}}

And I got F=22.24813

This was not the correct answer. I would appreciate any advice.

I attempted to find the velocity of the pulse : (0.943s)(3.29m)(8)=24.81976
 
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Try using this equation for velocity:

v=\omega/k
 
Am I right in assuming that 6950 is omega? The problem says 6950 /s, not radians/s. Is this still omega?
 
Yes, that is still omega.
 
That worked, thank you very much.
 
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