Two EE questions - nodal analysis and circuit modeling

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Two EE questions -- nodal analysis and circuit modeling

Homework Statement


Handwritten-style circuit schematic with a current source ia, resistor R1 (10 ohms) with voltage V1, a resistor R2 (20 ohms), a 4V1 dependent voltage source V3, and an ideal switch SW1 across R2 in a parallel branch.

Circuit diagram of a network with input and output terminal pairs; a 10 ohm resistor on the input side, a source voltage vi, and a 1 kilohm resistor on the output side with voltage vo. Below it, a graph of input voltage vi (V) against t (ms) from 0 to 1 ms, and a graph of output voltage vo (V) against t (ms) from 0 to 1 ms.

Two plots: input voltage v_i (V) versus t (ms), a sinusoid with peak about 5 V and trough about -5 V over 0 to 1 ms; below it, output voltage v_o (V) versus t (ms), a waveform rising to 4 V, flat near 4 V, falling to -3 V, flat, then rising back to 0 V.


Homework Equations


I was given R1, R2, and Iα(t), the time for the switch to closed (50μs<=t<=100μs)
The question is asking about the energy associated with 2 sources and dissipated in R1, R2.

The Attempt at a Solution


For the 1st question, part should be ok for me. But i have no idea on how to start the part b).take integration for Iα(t) (since Iα(t)=da/dt) , then obtain a i=(-1/5)e^-500t
but what value for the integrals? integrated from t = 50μs to 100μs? or from t = 0μs to 200μs ? then "I" can be found?
E=Pt, = (IV)t. What value of t will be used here for each source and resistor to find the energy?

For Q4, totally no idea on it. It is about the topic of diode?
 
In Q3, once you know the voltage & current associated with each element, the product of the two will be its power. Integration of power leads to energy.

Q4 does call for a diode arrangement.
 
NascentOxygen said:
In Q3, once you know the voltage & current associated with each element, the product of the two will be its power. Integration of power leads to energy.

Q4 does call for a diode arrangement.


Thanks so much for your reply.
After calculation I find :
I1: 2/7(ia)
I2: 5/7(ia)
I3= -5/7 ia
V1= 20/7 (ia)
V2= 100/7 ia

Then , power of R1 = v1 i1
I get 4000/49 e^-5000t
Then I need to integral it to find energy but what should I set for the upper and Lower intergal? Since the switch is closed for 50u<T< 100u, but the question asks for the energy for 0<T<200u, so which range should I use ?
And why?
 
You will have to evaluate the integral in pieces, until you have covered the full interval. The circuit changes when R2 is shorted out.