Under pressure -- flow rate through multiple holes in a pipe

AI Thread Summary
To calculate the total volume of air escaping through 40 holes in a pipe under a constant pressure of 350 mbar, one can use fluid dynamics equations that relate pressure drop, flow velocity, and Mach number. The velocity of air can be determined through trial and error using the formula M = v / c, where c is the speed of sound at 20°C. The density of the air is calculated based on the Mach number using the equation ρ_t = P_t / (R * T_t), where P_t is pressure in Pascals and T_t is temperature in Kelvin. After determining the velocity, it should be multiplied by the total exit area of the holes to find the volumetric flow rate in m³/hr. This approach provides a systematic way to estimate air flow in the described system.
Bruce Center
Messages
1
Reaction score
0
I am looking at air system that is under a constant pressure of 350 mbar into a pipe that has 40 - 2 mm round holes. Is there a formula that I can use to calculate the total volume of air nm3/hr that will escape the system?
Let's just say the air temp is constant.
Can anyone help with this?
 
Engineering news on Phys.org
On this website, you have the equations to define the velocity of your fluid based on your known pressure drop in the section Static, dynamic and total pressure, flow velocity and Mach number (\gamma = 1.4 for air). You will have to do trial and error to find it since M = v / c (where c = 343 m/s at 20°C, see speed of sound for air). The density \rho is defined in equation (8) based on Mach number where \rho_t = \frac{P_t}{RT_t} where P_t & T_t are the pressure (in Pa) and temperature (in K) of your air when at rest (may be your initial pressure and ambient temperature if your air inside the pipe can be assumed to be immobile) and R = 287 J/kg/K for air.

Then you multiply that velocity by your total exit area of your holes to get your volumetric flow rate. The velocity must in m/hr and the area in m² to get the answer in m³/hr.
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top