- #1
kr0z3n
- 8
- 0
I'm trying to understand the differential mode for a BJT. For the second picture, when we apply +1V to the base of Q1 and 0V to the base of Q2. Why is the emitter voltage .3V instead of -.7V? Similarity, for the third picture, why is the emitter voltage -.7V instead of 1.7V?
Thanks for the help!
Thanks for the help!