How Strong is the Electric Field Between Two Plates?

Thread starter Kajayacht
Start date Jan 16, 2008
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Electric Electric field Field Uniform

AI Thread Summary

The electric field strength between two plates separated by 1.2 cm with a potential difference of 25,000V is calculated using the formula E=V/D. Substituting the values, E equals 25,000V divided by 0.012m, resulting in an electric field of approximately 2,083,333.3 V/M. The calculation confirms that the problem has been correctly solved. There is no issue with the answer, as it has been verified. The discussion concludes with reassurance that the calculation is accurate.

Jan 16, 2008

Kajayacht

1. If the accelerating plates are 1.2cm apart and have a potential difference of 25,000V what is the magnitude of the electric field between them?
2. E=V/D
3. E=25,000V/1.2x10^-2m= 2083333.3 V/M

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Jan 16, 2008

foxjwill

So, what's the problem? It seems to me that you've already solved it.

Jan 16, 2008

Kajayacht

I didn't know if I got the question right...

Jan 16, 2008

foxjwill

You did. I checked it on my calculator.

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