Variation of electric field and potential along the axis of a cone

AI Thread Summary
The discussion centers on the variation of electric field (E) and potential (V) along the axis of a cone, with participants exploring the relationships between these quantities and current density (J). It is established that as distance from the cone's smaller surface increases, the area increases, leading to a decrease in charge density and a corresponding decrease in E, while V remains constant due to the relationship V=ER. Clarifications are sought regarding the algebraic dependencies of E and V on the distance 'a', with suggestions to express these relationships through differential equations. The conversation also addresses the constancy of current (I) and its implications for J and E, with participants correcting initial misunderstandings about these relationships. Overall, the thread emphasizes the need for precise mathematical formulations to fully understand the behavior of electric fields and potentials in this context.
Physics lover
Messages
249
Reaction score
25
Homework Statement
The electric field intensity potential and rate of heat generation per unit length aare E,V and H at a section distant a from left end of a conical shaped conductor connected to a battery of emf E.Find the correct options-:
Options are in attempt at a solution
Relevant Equations
J=sigmaE
V=IR
245216


Options are at the top of page as a) b) c) d)
Answer may more than one.
Now since 'a' is distance from the smaller surface of cone so as we move along the axis area will increase,So current charge density will decrease and as we know J=sigma E,E will decrease,but V will remain constant since V=Er and r is increasing and E decreasing.Now i don't if this is correct or not and further how will i find the relation between H and a and H and E.
 
Physics news on Phys.org
Your image misses the X axis label in d).
Please post the text of the question word for word, as another image say. Your precis is a bit vague.
If three quantities V, E and R are related by V=ER where R is increasing and E is decreasing, it does not follow that E is constant. You need to know more precisely how E and R depend on a.

Please post algebraic attempts at how E and V vary with a, perhaps as differential equations.
 
haruspex said:
Your image misses the X axis label in d).
Please post the text of the question word for word, as another image say. Your precis is a bit vague.
If three quantities V, E and R are related by V=ER where R is increasing and E is decreasing, it does not follow that E is constant. You need to know more precisely how E and R depend on a.

Please post algebraic attempts at how E and V vary with a, perhaps as differential equations.
In option d 'a' is on x axis.So how should i proceed further.
 
haruspex said:
Your image misses the X axis label in d).
Please post the text of the question word for word, as another image say. Your precis is a bit vague.
If three quantities V, E and R are related by V=ER where R is increasing and E is decreasing, it does not follow that E is constant. You need to know more precisely how E and R depend on a.

Please post algebraic attempts at how E and V vary with a, perhaps as differential equations.
Can you tell me which quantity will remain constant as move along axis.Is it I
 
Physics lover said:
Can you tell me which quantity will remain constant as move along axis.Is it I
Yes. In any period of time, the flow of charge into a given disc slice of the cone must equal the flow out.
 
haruspex said:
Yes. In any period of time, the flow of charge into a given disc slice of the cone must equal the flow out.
Ok i think i got it.since I is constant and J is increasing therefore E should increase by J=sigmaE. Am i coorect?
 
Physics lover said:
Ok i think i got it.since I is constant and J is increasing therefore E should increase by J=sigmaE. Am i coorect?
I don’t know what J represents in this context, nor what Es are being summed.
 
haruspex said:
I don’t know what J represents in this context, nor what Es are being summed.
J is current density.and J=sigma E is ohms law.Now can you help please.
 
Physics lover said:
J is increasing therefore E should increase by J=sigmaE.
But here you wrote
Physics lover said:
current charge density will decrease and as we know J=sigma E,E will decrease,
Why have you switched?
 
  • #10
haruspex said:
But here you wrote

Why have you switched?
Very sorry for the first one.That was wrong J will decrease as area is increasing isn't it.
 
  • #11
Physics lover said:
Very sorry for the first one.That was wrong J will decrease as area is increasing isn't it.
Can you please help me further.I could only tell about J and I.
 
  • #12
Physics lover said:
Can you please help me further.I could only tell about J and I.
I think it will help if you are more specific about the algebraic relationship.
Consider a thin disc width da at distance a from the point of the cone. What is its resistance? What is the potential across it? How much power is dissipated in it?
 
Back
Top