(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two workers pull horizontally on a heavy box, but one pulls twice as hard as the other. The larger pull is directed at 25.0 degrees west of north, and the resultant of these two pulls is 350.0 N directly northward.

Use vector components to find the magnitude of each of these pulls and the direction of the smaller pull.

2. Relevant equations

Vector A + VectorB = VectorR

Magnitude of R = 350

3. The attempt at a solution

Well, Since Rx = 0 = Ax + Bx then Ax=-Bx

and since Ay+By=350 then Ay=350-By and By=350-Ay

I know that Ay=A*cos(25)

and that Ax=A*sin(25)

Also that By=B*sin (x)

and Bx=B*cos(x) Where x is the angle from the x axis to the vector B.

A=2B since A is twice that length of B

So, the problem here is trying to get these things in terms of each other so that i can solve for only one variable.

I've figured out that since By=350-Ay then By=350-A*cos(25) which is equal to By=350-2B*cos(25).

So that's pretty much where I'm stuck. I know that there has to be some way to relate the fact that Ax=-Bx and A=2B and that the angle of 25 degrees for the C vector, that I have sufficient information to figure this problem out. It seems that I can never get it down to one variable. Maybe there's an equation that I'm forgetting. I've spent more than a few hours on this problem and I'm getting frustrated, it's the last problem in the assignment. I appreciate any help.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Vector Question of two workers

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