Vertical Circles/Work-related Physics

In summary, the first question deals with a 0.30 kg mass attached to a string swinging in a vertical circle with a radius of 1.6m. At an instant when the angle is 50 degrees, the tension in the string is 8.0N. The question asks for the magnitude of the resultant force on the mass at this instant.The second question involves a 4kg block moving down a 37 degree incline from point A to point B, with a horizontal force of 10N applied between the two points. The kinetic energy of the block at A is 10J and at B is 20J. The question asks for the work done on the block by the force of friction between A
  • #1
physixnot4me
27
0
What formula do i apply to the following/theories?

(1) a 0.30 kg mass attached to the end of a string swings in a vertical circle (R=1.6m). At an instant when theta=50 degrees, the tension in the string is 8.0N. what is the magnitude of the resultant force on the mass at this instant?

(2) a 4kg block is lowered down a 37 degree incline a distance of 5m from point A to point B. A horizontal force (F=10N) is applied to the block between A and B. the kinetic energy of the block at A is 10J and at B is 20J. How much work is done on the block by the force of friction between A and B?

(3)A rock attached to a string swings in a vertical circle. Which free body diagram could correctly describe the force(s) on the rock when the string is in one possible horizontal position?

**DIAGRAMS ARE ATTACHED** for all of the above questions.
 

Attachments

  • demo1.JPG
    demo1.JPG
    3.3 KB · Views: 405
  • demo3.JPG
    demo3.JPG
    14.9 KB · Views: 407
  • demo2.JPG
    demo2.JPG
    6.2 KB · Views: 477
Physics news on Phys.org
  • #2
You have to show your work to receive help. That is one of the rules you agreed to.
 
  • #3


For the first question, the formula that can be applied is the centripetal force equation: Fc = mv^2/r, where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius of the circle. In this case, the resultant force on the mass can be calculated by subtracting the tension force from the centripetal force.

For the second question, the formula that can be applied is the work-energy theorem: W = ΔKE + ΔPE, where W is work done, ΔKE is the change in kinetic energy, and ΔPE is the change in potential energy. In this case, the work done by the force of friction can be calculated by subtracting the change in kinetic energy from the change in potential energy.

For the third question, the correct free body diagram would show the weight of the rock acting downwards, the tension force acting upwards, and the centripetal force acting towards the center of the circle. This is because when the string is in a horizontal position, the weight and tension forces are balanced, and the centripetal force is the only force causing the rock to move in a circular motion.
 

Related to Vertical Circles/Work-related Physics

1. What is a vertical circle in physics?

A vertical circle in physics is a circular motion that occurs when an object moves along a curved path in a vertical plane, with its direction constantly changing. This type of motion is influenced by the force of gravity and can be seen in many real-life scenarios, such as a rollercoaster or a satellite orbiting Earth.

2. How does centripetal force relate to vertical circles?

In vertical circles, centripetal force is the force that keeps an object moving in a circular path. This force acts towards the center of the circle and is responsible for constantly changing the direction of the object's motion. In the case of a vertical circle, centripetal force is provided by the force of gravity, pulling the object towards the center of the circle.

3. What is the work-energy theorem in relation to vertical circles?

The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. In vertical circles, work is done by the force of gravity on the object, causing it to move in a circular path. This work is then converted into kinetic energy, which is constantly changing as the object moves through different points in the circle.

4. How does the radius of the circle affect the speed of an object in a vertical circle?

The radius of the circle has a direct effect on the speed of an object in a vertical circle. As the radius decreases, the speed of the object increases, and vice versa. This is because the centripetal force required to keep the object in the circular path remains constant, but the velocity of the object changes as it moves through different points in the circle.

5. What is the difference between uniform and non-uniform circular motion in vertical circles?

In uniform circular motion, the speed of the object remains constant throughout the circular path, while in non-uniform circular motion, the speed changes at different points in the circle. In vertical circles, an object can experience both types of motion, depending on the forces acting on it. For example, a rollercoaster may experience non-uniform circular motion as it speeds up and slows down at different points, but a satellite in orbit experiences uniform circular motion as it maintains a constant speed.

Similar threads

  • Introductory Physics Homework Help
Replies
16
Views
4K
  • Introductory Physics Homework Help
Replies
15
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
16
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
919
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
4K
Back
Top