Very easy simple harmonic motion question that I keep getting wrong

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Homework Help Overview

The problem involves simple harmonic motion, specifically the oscillation of a piston in an engine described by a cosine function. The original poster seeks to determine the velocity of the piston at a specific time, t = 0, using the provided position function.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the velocity by taking the derivative of the position function and substituting the time value. They express confusion over their calculated result being significantly off from the expected answer.

Discussion Status

Some participants have offered guidance regarding the correct form of the velocity equation, suggesting that the original poster may have overlooked the need to include the angular frequency in their calculations. There is an acknowledgment of a misunderstanding in applying the derivative correctly.

Contextual Notes

Participants note that the original poster's calculations may not align with the expected units for velocity, indicating a potential misunderstanding of the relationship between amplitude, angular frequency, and the sine function in the context of simple harmonic motion.

coldjeanz
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Homework Statement



In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the following expression, where x is in centimeters and t is in seconds.

x = (7.00 cm) cos(4t + π/6)

At t = 0, what is its velocity?

Homework Equations



v(t) = -A sin(ωt + ϕ)

The Attempt at a Solution



It first asked me to find the position so I did that easily by plugging in for time and getting an answer. And to get velocity I just had to take the derivative of the initial function and then plug in once again. However, when I do this I do not get the correct answer and I can't figure out why.

The expression should read

v(t) = -7.00 cm sin (4(0) + π/6)

This basicaly breaks down to -7.00 * 1/2 right?

When I do this I get -3.5 cm/s and it says my answer is off by more than 10%. No idea what I am doing wrong.
 
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coldjeanz said:

Homework Statement



In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the following expression, where x is in centimeters and t is in seconds.

x = (7.00 cm) cos(4t + π/6)

At t = 0, what is its velocity?

Homework Equations



v(t) = -A sin(ωt + ϕ)


The Attempt at a Solution



It first asked me to find the position so I did that easily by plugging in for time and getting an answer. And to get velocity I just had to take the derivative of the initial function and then plug in once again. However, when I do this I do not get the correct answer and I can't figure out why.

The expression should read

v(t) = -7.00 cm sin (4(0) + π/6)

This basicaly breaks down to -7.00 * 1/2 right?

When I do this I get -3.5 cm/s and it says my answer is off by more than 10%. No idea what I am doing wrong.

The expression in red above is not correct. It should be:

v(t) = -Aωsin(ωt + ϕ)

Since you know how to take a derivative, you can verify this for yourself. You can also see that the units work out in this case. The amplitude of the velocity has to have units of cm/s, not just cm.
 
Check your derivative carefully. While d/dt cos(t) = -sin(t), d/dt cos(ωt) ≠ -sin(ωt)...
 
Ah ok I was forgetting to multiply my Amplitude by ω

Got it thanks
 

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