Very Very simple question on dimensions of equation

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The discussion revolves around the dimensional analysis of the equation e²cħ/R, where e represents electric charge, c is the speed of light, ħ is the reduced Planck constant, and R is the radius. It is debated whether this expression has dimensions of energy; the analysis shows that cħ/R indeed has dimensions of energy, but multiplying by e² results in dimensions of (charge)²*(energy), which does not equate to energy. Additionally, the conversation touches on the method of checking dimensions using the LMT system, confirming that mass and time dimensions can be manipulated algebraically. The participants emphasize the importance of consistency in units and suggest treating units as algebraic variables for clarity. Overall, the discussion highlights the complexities of dimensional analysis in physics equations.
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My teacher said

e2 c x ħ/R

Where e is the electric charge, c is speed of light and h is reduced constant and R is radius.

My teacher said this has dimenions of energy, is this right?
 
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c ħ/R has dimensions of (distance/time)*(energy*time)/(distance), or energy.

Multiplying by the square of the electrical charge yields (charge)2*(energy), which does not have dimensions of energy.
 
D H said:
c ħ/R has dimensions of (distance/time)*(energy*time)/(distance), or energy.

Multiplying by the square of the electrical charge yields (charge)2*(energy), which does not have dimensions of energy.

Ok thank you. I have another question. My teacher was showing us a way to check the dimensions of equations. He showed us this

LMT

So if something has mass x t dimensions, it can be given as

LMT/L

it can also be written as L-1MT is this right?

If I wanted to multiply two values together, let us say MT times T this is just

MT2

right?

How do you calculate something like

LMT/M2

Thanks
 
What the teacher is telling you is fine so long as you don't mix up, say, seconds and hours or meters and centimeters, etc.

MT times T is MT^2

LMT/M^2 = L(M^-1) T

In my opinion the better way to do it is put the units into the expression and handle them just like the units are typical algebraic variables and see if the units remaining in the expression are what you seek.
 
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