Viscosity,Fluid flow and terimal velocity

  • Thread starter Thread starter ChunkymonkeyI
  • Start date Start date
  • Tags Tags
    Flow Velocity
AI Thread Summary
The discussion centers on the relationship between buoyancy force (Fb), drag force (FD), and gravitational force (Fg) in fluid dynamics. It highlights that Fb equals FD when an object reaches terminal velocity, where the forces balance out. The equations for buoyancy and drag forces are provided, with Fb calculated using the density of water and the volume of the object, while FD is determined by viscosity and the object's radius. The confusion arises regarding the scenario of a sphere falling through water and how to prove the conditions for terminal velocity. Clear communication is emphasized, with a reminder to use proper language in the discussion.
ChunkymonkeyI
Messages
35
Reaction score
0

Homework Statement


When does Fb(Buoyancy force) equal the drag force(FD)?
and Fb+FD=Fg

Homework Equations


Fb=density of water times volume of water times 9.80 m/s^2
FD=6pi times viscosity times radius times v
Fg=mg

The Attempt at a Solution


All ik is the solid has 2 be in the air going to the water but idk how 2 really prove that please help me
 
Physics news on Phys.org
This problem is really confusing. Do we have a ball falling in water? Not sure what is going on here.
 
It is a sphere of radius r moving with speed v in a fluid of viscosity η. The drag force is FD=6πηrv.
The buoyant force is FB=ρVg, where ρ is the density of the liquid and V is the volume of the sphere.

ehild

PS: ChunkymonkeyI, what did you mean: "All ik is the solid has 2 be in the air going to the water but idk how 2 really prove that please help me" We use English here.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top