Volume of Revolved Area Bounded by ln(x) and the x-axis

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The discussion revolves around a final exam question regarding the volume of a solid of revolution formed by the area bounded by y=ln(x), the x-axis, and x=e, when revolved around the line x=-1. The cylindrical shell method and washer method were used to set up the integrals for calculating the volume. The correct setup for the cylindrical shell method is 2π∫[1 to e] ln(x)(x + 1)dx, while the washer method should be π∫[0 to 1] ((e + 1)² - (e^y + 1)²)dy. The poster confirmed that they had at least one correct integral setup and acknowledged a mistake in their initial post by omitting the factor of 2π in the last integral. Overall, the focus is on verifying the correctness of the integral setups for the volume calculation.
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Quesion on my final today!

I had the following question on my final exam today and i was wondering if i did it correctly:

Let y=\ln{x}\ bounded by x=eand the x-axis. Create a solid of revonution by revolving the are of R about the the line x=-1.

(a) use the cylindrical shell method.

(b) use the washer method


to find the volume of R.

We didn't have to evaluate the integrals. we just had to set them up
are my ansewers below correct? thanks in advance.

\pi\int_{0}^{1}{(e^y + 1)^2-1^2}dy

\2\pi\int_{1}^e\ln{x}(x +1)dx
 
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RadiationX said:
I had the following question on my final exam today and i was wondering if i did it correctly:

Let y=\ln{x}\ bounded by x=eand the x-axis. Create a solid of revonution by revolving the are of R about the the line x=-1.

(a) use the cylindrical shell method.

(b) use the washer method


to find the volume of R.

We didn't have to evaluate the integrals. we just had to set them up
are my ansewers below correct? thanks in advance.

\pi\int_{0}^{1}{(e^y + 1)^2-1^2}dy

\2\pi\int_{1}^e\ln{x}(x +1)dx

I finally got these:
cylindrical shell: 2\pi\int_{1}^e\ln{x}(x +1)dx

washer: \pi\int_{0}^{1}{(e + 1)^2-(e^y + 1)^2}dy
 
i got at least one correct. in my post i left off the 2pi for the last integral.thx
 
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