1. The problem statement, all variables and given/known data Given a cube that is 60% porous, and you subject it to a very large pressure such that the pores close completely, what is the dilatation of the cube? 2. Relevant equations Dilatation (Δ) = ΔV/Vo where Vo is the original volume. Vnew equals = (∂x-εxx∂x)(∂y - εyy∂y)(∂z - εzz∂z) εxx= change in side parallel to x-axis/ (original side) 3. The attempt at a solution Say the original side, x=1, and since we're working with a cube, then (∂x-εxx∂x)3 = V . So, Solving for εxx = (0.4x-x)/x= -0.6. Then Dilatation (Δ) = ΔV/V = (1 - 0.6)^3 - 1 / 1 = -0.936 Is this logic correct? I am trying to solve for dilatation of the cube if it shrinks, say, by 60%. Thanks for your help.