Wave functions and probability

Click For Summary

Homework Help Overview

The discussion revolves around the application of wave functions in quantum mechanics, specifically focusing on a normalized wave function for a particle and the calculation of probability density in three-dimensional space.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to apply the theory of wave functions to compute the probability of finding a particle within a specific distance from the origin. They express confusion regarding the normalization of the wave function and the integration process required to find the probability density.
  • Some participants question the normalization of the wave function and clarify the relationship between probability density and the volume element in spherical coordinates.
  • Others suggest revisiting the derivation of the integral formula for probability density and its application in this context.

Discussion Status

The discussion is ongoing, with participants providing clarifications and addressing misunderstandings about the normalization of the wave function and the integration process. There is a recognition of the need for further exploration of the concepts involved, particularly regarding the derivation of probability density in quantum mechanics.

Contextual Notes

Participants note the absence of specific details regarding the domain of the wave function and express uncertainty about the integration process required for calculating probabilities. The original poster is encouraged to revisit their lecture notes for additional context.

ariana13
Messages
8
Reaction score
0

Homework Statement


I've had lectures on the theory of this topic, but I've not been given any examples and I'm struggling with how to apply the theory to this homework question:
A particle is described by the normalised wave function

Si(x,y,z)=Ae^-h(x^2+y^2+z^2) where A and h are real positive constants.

Determine the probability of finding the particle at a distance between r and r+dr from the origin.


Homework Equations


p=integral (mod[Si(x,y,z)])^2 dxdydz


The Attempt at a Solution


I thought that the wave function was supposed to involve complex numbers, but there's no i in the wave function? I thought i needed the conjugate of the wave function to find mod[Si(x,y,z)]?
I think once i find (mod[Si(x,y,z)])^2 i then need to integrate it over the volume of a spherical shell with radius r and thickness dr, so r^2=x^2+y^2+z^2 but I'm confused about how to compute this integral. Do i need to parametrise the variables?

I'm obviously not asking for someone to give me the solution, but I'm having a hard time figuring out where to start with this problem, so any help would be greatly appreciated.
 
Physics news on Phys.org
Your wavefunction is not normalized! Was there a specific finite domain where it was non-zero and you forgot to include that in your post?

Anyway you are not evaluating an integral. The probability you are looking for is |\psi|^2 dV = |\psi|^2 4\pi r^2 dr.
 
No, i copied the question down word for word, it says that the wave function is normalised! I'm sorry, I'm still very confused because it says in my lecture notes that i have to integrate to find the probability. Can you please tell me where you get |\psi|^2 dV = |\psi|^2 4\pi r^2 dr from?
 
Elementary probability theory--

The probability of a variable X assuming a value between X=x and X=x+dx is

dP=\rho(x)dx
where \rho is the probability density.

You need that local probability so that you can integrate it to obtain global ones. The integral formula comes from this. The exercise is meant to see if you were paying attention to the derivation.
 
I was paying attention in the derivation, i just found it a bit hard to follow. Thankyou for your help, I'll the question another go.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
803
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
947
Replies
3
Views
2K
Replies
4
Views
2K
Replies
9
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
64
Views
5K